Logarithm Calculation: Log Base 3 Of 46

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Understanding Logarithms

Logarithms are a fundamental concept in mathematics, often described as the inverse operation to exponentiation. In simpler terms, if we have an exponential equation like bx=yb^x = y, the corresponding logarithmic equation is logby=x\log_b y = x. Here, bb is the base of the logarithm, yy is the argument, and xx is the exponent. The question 'What is the logarithm of yy to the base bb?' is essentially asking 'To what power must we raise the base bb to get yy?'

In our specific problem, we need to evaluate log346\log_3 46. This means we are looking for a number, let's call it xx, such that 3x=463^x = 46. Finding this value of xx directly can be challenging, especially when the argument (46) is not a simple power of the base (3). Fortunately, we have tools and techniques to approximate or calculate such values, often requiring a calculator or computational software. The requirement to round the answer to the nearest thousandth indicates that an exact integer or simple fraction is unlikely, and we will be dealing with a decimal approximation.

Logarithms are incredibly powerful tools used across various fields, including science, engineering, finance, and computer science. They help us simplify complex calculations, model exponential growth and decay, and solve equations that would otherwise be intractable. For instance, in computer science, logarithms are crucial for analyzing the efficiency of algorithms. The time complexity of many sorting algorithms, like merge sort, is expressed using logarithms, typically logn\log n or log2n\log^2 n, where nn is the number of items to be sorted. This tells us how the execution time of an algorithm scales as the input size increases. In finance, logarithms are used in compound interest calculations and in determining the time it takes for an investment to grow to a certain value. The formula for compound interest involves exponential growth, and taking the logarithm allows us to solve for time or interest rates.

Furthermore, logarithms are essential in fields like acoustics (decibel scale for sound intensity), seismology (Richter scale for earthquake magnitude), and chemistry (pH scale for acidity). The reason logarithms are so widely applicable is their ability to transform multiplicative relationships into additive ones. For example, the logarithm of a product is the sum of the logarithms: log(ab)=loga+logb\log(ab) = \log a + \log b. This property is immensely useful for simplifying calculations and understanding relationships between variables. When dealing with very large or very small numbers, logarithms can bring them into a more manageable range, making comparisons and analyses easier.

The Change of Base Formula

When a calculator or computational tool doesn't directly support a specific base for a logarithm, we can use the change of base formula. This formula allows us to convert a logarithm from any base to a more convenient base, usually base 10 (common logarithm, denoted as log\log or log10\log_{10}) or base ee (natural logarithm, denoted as ln\ln or loge\log_e). The formula states that for any positive numbers aa, bb, and xx where a1a \neq 1 and b1b \neq 1:

logbx=logaxlogab\log_b x = \frac{\log_a x}{\log_a b}

In our case, we want to calculate log346\log_3 46. Using the change of base formula with the natural logarithm (base ee), we get:

log346=ln46ln3\log_3 46 = \frac{\ln 46}{\ln 3}

Alternatively, we could use the common logarithm (base 10):

log346=log46log3\log_3 46 = \frac{\log 46}{\log 3}

Both of these expressions will yield the same numerical result. This formula is incredibly useful because most scientific calculators and programming languages provide built-in functions for ln\ln and log\log. Without it, calculating logarithms of arbitrary bases would be significantly more difficult.

Why is the change of base formula so important? Imagine you have a calculator that only has buttons for log10\log_{10} and ln\ln. If you need to find log215\log_2 15, you can't just plug it in directly. But by using the change of base formula, you can convert it into a calculation you can do: log1015log102\frac{\log_{10} 15}{\log_{10} 2} or ln15ln2\frac{\ln 15}{\ln 2}. This unlocks the ability to compute logarithms of any base, as long as you have access to logarithms of one or two standard bases. This is a cornerstone of computational mathematics and practical applications of logarithms.

The derivation of the change of base formula itself is quite elegant and stems directly from the definition of logarithms and the properties of exponents. Let y=logbxy = \log_b x. By definition, this means by=xb^y = x. Now, take the logarithm of both sides of this equation with respect to a new base, say aa: loga(by)=logax\log_a (b^y) = \log_a x. Using the power rule of logarithms (which states loga(Mp)=plogaM\log_a (M^p) = p \log_a M), we can rewrite the left side as ylogab=logaxy \log_a b = \log_a x. Now, we can solve for yy by dividing both sides by logab\log_a b (assuming logab0\log_a b \neq 0, which is true since b1b \neq 1): y=logaxlogaby = \frac{\log_a x}{\log_a b}. Since we initially defined y=logbxy = \log_b x, we have successfully derived the change of base formula: logbx=logaxlogab\log_b x = \frac{\log_a x}{\log_a b}. This demonstrates the fundamental consistency and interconnectedness of logarithmic properties.

Calculation and Rounding

To evaluate log346\log_3 46, we will use the change of base formula with the natural logarithm:

log346=ln46ln3\log_3 46 = \frac{\ln 46}{\ln 3}

Using a calculator:

  • ln463.828641396\ln 46 \approx 3.828641396
  • ln31.098612289\ln 3 \approx 1.098612289

Now, we divide these values:

log3463.8286413961.0986122893.485170966\log_3 46 \approx \frac{3.828641396}{1.098612289} \approx 3.485170966

We are asked to round the answer to the nearest thousandth. The thousandths place is the third digit after the decimal point. In our result, 3.4851709663.485170966, the digit in the thousandths place is 5. The digit immediately to its right is 1. Since 1 is less than 5, we round down, meaning the thousandths digit remains 5.

Therefore, log346\log_3 46 rounded to the nearest thousandth is 3.4853.485.

Let's double-check our understanding of rounding. Rounding to the nearest thousandth means we want to find the multiple of 0.001 that is closest to our calculated value. Our value is approximately 3.485173.48517. The two closest multiples of 0.001 are 3.4853.485 and 3.4863.486. To determine which one is closer, we look at the digit in the ten-thousandths place, which is 1. Since 1<51 < 5, the number is closer to 3.4853.485. If the digit had been 5 or greater, we would round up to 3.4863.486. This careful attention to the subsequent digit is crucial for accurate rounding.

It's also worth noting that the value 3.4853.485 means that 33.4853^{3.485} should be approximately equal to 46. Let's verify this using a calculator: 33.48545.9783^{3.485} \approx 45.978. This is very close to 46, confirming our rounded answer is correct. If we had rounded to 3.4863.486, we would have 33.48646.0353^{3.486} \approx 46.035, which is slightly further away from 46 than 45.97845.978.

This process of evaluation and rounding is fundamental in applied mathematics and science, where theoretical values often need to be expressed in a practical, usable format. Whether it's reporting experimental results, making engineering calculations, or modeling financial scenarios, precision and appropriate rounding are key to conveying information effectively and ensuring subsequent calculations are based on accurate approximations.

Conclusion

In summary, to evaluate log346\log_3 46, we recognized it as finding the exponent xx such that 3x=463^x = 46. Due to the nature of the numbers, we employed the change of base formula to convert the problem into a calculation using natural logarithms: log346=ln46ln3\log_3 46 = \frac{\ln 46}{\ln 3}. After performing the calculation, we obtained a value of approximately 3.4851709663.485170966. Finally, by rounding to the nearest thousandth, as requested, we arrived at the answer 3.4853.485.

Logarithms are a powerful mathematical concept with wide-ranging applications. Understanding how to evaluate them, especially using the change of base formula when necessary, is a valuable skill. For further exploration into the fascinating world of logarithms and their uses, you might find resources like Khan Academy's logarithm section to be very helpful.